Integrand size = 13, antiderivative size = 103 \[ \int \frac {x^2}{\sqrt {1+x^4}} \, dx=\frac {x \sqrt {1+x^4}}{1+x^2}-\frac {\left (1+x^2\right ) \sqrt {\frac {1+x^4}{\left (1+x^2\right )^2}} E\left (2 \arctan (x)\left |\frac {1}{2}\right .\right )}{\sqrt {1+x^4}}+\frac {\left (1+x^2\right ) \sqrt {\frac {1+x^4}{\left (1+x^2\right )^2}} \operatorname {EllipticF}\left (2 \arctan (x),\frac {1}{2}\right )}{2 \sqrt {1+x^4}} \]
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Time = 0.01 (sec) , antiderivative size = 103, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 3, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.231, Rules used = {311, 226, 1210} \[ \int \frac {x^2}{\sqrt {1+x^4}} \, dx=\frac {\left (x^2+1\right ) \sqrt {\frac {x^4+1}{\left (x^2+1\right )^2}} \operatorname {EllipticF}\left (2 \arctan (x),\frac {1}{2}\right )}{2 \sqrt {x^4+1}}-\frac {\left (x^2+1\right ) \sqrt {\frac {x^4+1}{\left (x^2+1\right )^2}} E\left (2 \arctan (x)\left |\frac {1}{2}\right .\right )}{\sqrt {x^4+1}}+\frac {\sqrt {x^4+1} x}{x^2+1} \]
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Rule 226
Rule 311
Rule 1210
Rubi steps \begin{align*} \text {integral}& = \int \frac {1}{\sqrt {1+x^4}} \, dx-\int \frac {1-x^2}{\sqrt {1+x^4}} \, dx \\ & = \frac {x \sqrt {1+x^4}}{1+x^2}-\frac {\left (1+x^2\right ) \sqrt {\frac {1+x^4}{\left (1+x^2\right )^2}} E\left (2 \tan ^{-1}(x)|\frac {1}{2}\right )}{\sqrt {1+x^4}}+\frac {\left (1+x^2\right ) \sqrt {\frac {1+x^4}{\left (1+x^2\right )^2}} F\left (2 \tan ^{-1}(x)|\frac {1}{2}\right )}{2 \sqrt {1+x^4}} \\ \end{align*}
Result contains higher order function than in optimal. Order 5 vs. order 4 in optimal.
Time = 10.01 (sec) , antiderivative size = 22, normalized size of antiderivative = 0.21 \[ \int \frac {x^2}{\sqrt {1+x^4}} \, dx=\frac {1}{3} x^3 \operatorname {Hypergeometric2F1}\left (\frac {1}{2},\frac {3}{4},\frac {7}{4},-x^4\right ) \]
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Result contains higher order function than in optimal. Order 5 vs. order 4.
Time = 4.13 (sec) , antiderivative size = 17, normalized size of antiderivative = 0.17
method | result | size |
meijerg | \(\frac {x^{3} {}_{2}^{}{\moversetsp {}{\mundersetsp {}{F_{1}^{}}}}\left (\frac {1}{2},\frac {3}{4};\frac {7}{4};-x^{4}\right )}{3}\) | \(17\) |
default | \(\frac {i \sqrt {-i x^{2}+1}\, \sqrt {i x^{2}+1}\, \left (F\left (x \left (\frac {\sqrt {2}}{2}+\frac {i \sqrt {2}}{2}\right ), i\right )-E\left (x \left (\frac {\sqrt {2}}{2}+\frac {i \sqrt {2}}{2}\right ), i\right )\right )}{\left (\frac {\sqrt {2}}{2}+\frac {i \sqrt {2}}{2}\right ) \sqrt {x^{4}+1}}\) | \(82\) |
elliptic | \(\frac {i \sqrt {-i x^{2}+1}\, \sqrt {i x^{2}+1}\, \left (F\left (x \left (\frac {\sqrt {2}}{2}+\frac {i \sqrt {2}}{2}\right ), i\right )-E\left (x \left (\frac {\sqrt {2}}{2}+\frac {i \sqrt {2}}{2}\right ), i\right )\right )}{\left (\frac {\sqrt {2}}{2}+\frac {i \sqrt {2}}{2}\right ) \sqrt {x^{4}+1}}\) | \(82\) |
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Result contains complex when optimal does not.
Time = 0.10 (sec) , antiderivative size = 44, normalized size of antiderivative = 0.43 \[ \int \frac {x^2}{\sqrt {1+x^4}} \, dx=\frac {i \, \sqrt {i} x E(\arcsin \left (\frac {\sqrt {i}}{x}\right )\,|\,-1) - i \, \sqrt {i} x F(\arcsin \left (\frac {\sqrt {i}}{x}\right )\,|\,-1) + \sqrt {x^{4} + 1}}{x} \]
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Result contains complex when optimal does not.
Time = 0.35 (sec) , antiderivative size = 29, normalized size of antiderivative = 0.28 \[ \int \frac {x^2}{\sqrt {1+x^4}} \, dx=\frac {x^{3} \Gamma \left (\frac {3}{4}\right ) {{}_{2}F_{1}\left (\begin {matrix} \frac {1}{2}, \frac {3}{4} \\ \frac {7}{4} \end {matrix}\middle | {x^{4} e^{i \pi }} \right )}}{4 \Gamma \left (\frac {7}{4}\right )} \]
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\[ \int \frac {x^2}{\sqrt {1+x^4}} \, dx=\int { \frac {x^{2}}{\sqrt {x^{4} + 1}} \,d x } \]
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\[ \int \frac {x^2}{\sqrt {1+x^4}} \, dx=\int { \frac {x^{2}}{\sqrt {x^{4} + 1}} \,d x } \]
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Timed out. \[ \int \frac {x^2}{\sqrt {1+x^4}} \, dx=\int \frac {x^2}{\sqrt {x^4+1}} \,d x \]
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